Dúvida teórica sobre variação de entalpia
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PiR2 :: Química :: Físico-Química
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Dúvida teórica sobre variação de entalpia
Com base no seguinte quadro de entalpias de ligação, assinale a alternativa que apresenta o valor da entalpia de formação da água gasosa.
![Dúvida teórica sobre variação de entalpia 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)
(A) – 243 kJ mol–1 (B) – 134 kJ mol–1 (C) + 243kJ mol–1 (D) + 258 kJ mol–1 (E) + 1532 kJ mol–1
Minha dúvida sobre essa questão é mais teórica, uma vez que consegui resolvê-la: por que é possível achar o valor da entalpia de formação de um produto através da entalpia de suas ligações? A entalpia de formação de um composto, então, não difere de sua entalpia de ligação?
(A) – 243 kJ mol–1 (B) – 134 kJ mol–1 (C) + 243kJ mol–1 (D) + 258 kJ mol–1 (E) + 1532 kJ mol–1
- Gabarito:
- A
Minha dúvida sobre essa questão é mais teórica, uma vez que consegui resolvê-la: por que é possível achar o valor da entalpia de formação de um produto através da entalpia de suas ligações? A entalpia de formação de um composto, então, não difere de sua entalpia de ligação?
guuigo- Recebeu o sabre de luz
- Mensagens : 119
Data de inscrição : 20/08/2023
Re: Dúvida teórica sobre variação de entalpia
A entalpia de formação é essencialmente composta pelo saldo entre energia liberada pela ligação do produto e a consumida para a quebra dos reagentes. É claro que na vida real não é assim que as ligações são feitas, mas esses valores tabelados funcionam e são basicamente brincar de Lego.
Pois muito que bem, você parte de H-H + 1/2 O=O e chega em H - O - H: libera 2 E(O-H), mas consome E(H-H) + 1/2 (O=O) => Hf = -2(464) + (436) + 1/2 (498) = -243 kJ/mol.
Pois muito que bem, você parte de H-H + 1/2 O=O e chega em H - O - H: libera 2 E(O-H), mas consome E(H-H) + 1/2 (O=O) => Hf = -2(464) + (436) + 1/2 (498) = -243 kJ/mol.
Lipo_f- Jedi
- Mensagens : 357
Data de inscrição : 16/05/2024
Idade : 19
Localização : Belém, Pará
Re: Dúvida teórica sobre variação de entalpia
Lipo_f escreveu:A entalpia de formação é essencialmente composta pelo saldo entre energia liberada pela ligação do produto e a consumida para a quebra dos reagentes. É claro que na vida real não é assim que as ligações são feitas, mas esses valores tabelados funcionam e são basicamente brincar de Lego.
Pois muito que bem, você parte de H-H + 1/2 O=O e chega em H - O - H: libera 2 E(O-H), mas consome E(H-H) + 1/2 (O=O) => Hf = -2(464) + (436) + 1/2 (498) = -243 kJ/mol.
Então realmente é possível achar o valor da entalpia de formação de um produto através da energia de suas ligações, isso?
guuigo- Recebeu o sabre de luz
- Mensagens : 119
Data de inscrição : 20/08/2023
Lipo_f- Jedi
- Mensagens : 357
Data de inscrição : 16/05/2024
Idade : 19
Localização : Belém, Pará
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