Inequação exponencial com função modular

[latex]\\\mathrm{Por\ def.:|x|=\left\{\begin{matrix} \mathrm{x,se\ x \geq 0}\\ \mathrm{-x,se\ x < 0} \end{matrix}\right.}\\\\ \mathrm{Caso\ 1)\ x \geq 0\ (A)\ \therefore \ x^{3x^2-4x-4} > 1\to (3x^2-4x-4)log(x) > 0}\\\\ \mathrm{(x-2)(3x+2)log(x) > 0\to -\frac{2}{3} < x < 1\ \cup \ x > 2\ (B)}\\\\ \mathrm{(A)\ \cap \ (B)\to 0 \leq x < 1\ \cup \ x > 2}\\\\\mathrm{Mas\ note\ que\ f(x)=log(x)\ imp\tilde{o}e\ x > 0,logo:0 < x < 1\ \cup\ x > 2\ (C)}\\\\ \mathrm{Caso\ 2)\ x < 0\ (D)\ \therefore\ (-x)^{3x^2-4x-4} > 1\to (3x^2-4x-4)log(-x) > 0}\\\\ \mathrm{(x-2)(3x+2)log(-x) > 0\to x < - 1\ \cup\ -\frac{2}{3} < x < 2\ (E)}\\\\ \mathrm{(D)\ \cap\ (E)\to x < - 1\ \cup\ -\frac{2}{3} < x < 0}\\\\ \mathrm{S=[(C)]\ \cup\ [(D)\ \cap\ (E)]=\left \{ x < - 1,-\frac{2}{3} < x < 0, 0 < x < 1\ , x > 2 \right \}}[/latex]